1. The problem is to find the equation of the line that fits the given table of values for $x$ and $y$: $$\begin{array}{c|c} x & y \\ \hline -1 & 11 \\ 0 & 8 \\ 1 & 5 \\ 2 & 2 \end{array}$$ 2. We use the slope-intercept form of a line: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. Calculate the slope $m$ using two points, for example $(0,8)$ and $(1,5)$: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 8}{1 - 0} = \frac{-3}{1} = -3$$ 4. Now use the slope and one point to find $b$. Using point $(0,8)$: $$y = mx + b \Rightarrow 8 = (-3)(0) + b \Rightarrow b = 8$$ 5. The equation of the line is: $$y = -3x + 8$$ 6. Verify with another point, for example $x = -1$: $$y = -3(-1) + 8 = 3 + 8 = 11$$ which matches the table. Therefore, the equation of the line fitting the data is: $$\boxed{y = -3x + 8}$$