Subjects algebra

Line Equation B5F07E

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1. **State the problem:** Find the equation of the line $n$ passing through points $A(-1, 2)$ and $B(0, -2)$ in the form $y = mx + c$. 2. **Formula used:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ The equation of the line is then: $$y = mx + c$$ where $c$ is the $y$-intercept. 3. **Calculate the slope $m$:** $$m = \frac{-2 - 2}{0 - (-1)} = \frac{-4}{1} = -4$$ 4. **Find $c$ by substituting one point (use point B(0, -2)) into $y = mx + c$:** $$-2 = (-4)(0) + c$$ $$-2 = 0 + c$$ $$c = -2$$ 5. **Write the equation of the line:** $$y = -4x - 2$$ **Final answer:** The equation of line $n$ is $y = -4x - 2$.
A(-1,2)B(0,-2)