1. **State the problem:** We need to find the equation of the line shown on the graph in the form $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept.
2. **Identify two points on the line:** From the graph, two clear points are $(0, 1)$ and $(1, 3)$.
3. **Calculate the slope $m$:** The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$
Using points $(0,1)$ and $(1,3)$:
$$m = \frac{3 - 1}{1 - 0} = \frac{2}{1} = 2$$
4. **Find the y-intercept $c$:** The y-intercept is the value of $y$ when $x=0$. From the point $(0,1)$, we see $c = 1$.
5. **Write the equation:** Substitute $m=2$ and $c=1$ into $y = mx + c$:
$$y = 2x + 1$$
**Final answer:**
$$y = 2x + 1$$
Line Equation C0Bb28
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