Subjects algebra

Line Equation Cfd619

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1. **State the problem:** Find the equation of the straight line passing through the points $(0,6)$ and $(2,0)$ in the form $y = mx + c$. 2. **Formula used:** The equation of a line is $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 6}{2 - 0} = \frac{-6}{2} = -3$$ 4. **Find the y-intercept $c$:** Since the line passes through $(0,6)$, the y-intercept is $c = 6$. 5. **Write the equation:** Substitute $m = -3$ and $c = 6$ into $y = mx + c$: $$y = -3x + 6$$ **Final answer:** $$y = -3x + 6$$