1. **State the problem:** Find the equation of line H in the form $y = mx + c$ given two points on the line: $(-10, 70)$ and $(10, -30)$. 2. **Formula used:** The slope $m$ of a line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Calculate the slope:** $$m = \frac{-30 - 70}{10 - (-10)} = \frac{-100}{20} = -5$$ 4. **Use point-slope form to find $c$:** The equation is $y = mx + c$, so plug in one point, say $(-10, 70)$: $$70 = -5 \times (-10) + c$$ $$70 = 50 + c$$ $$c = 70 - 50 = 20$$ 5. **Final equation:** $$y = -5x + 20$$ This is the equation of line H in slope-intercept form.