1. **State the problem:** We are given two points on a coordinate plane and need to find the equation of the line passing through these points. 2. **Identify the points:** From the description, the points are approximately $(-4, -1)$ and $(-3, -2)$. 3. **Formula used:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 4. **Calculate the slope:** $$m = \frac{-2 - (-1)}{-3 - (-4)} = \frac{-2 + 1}{-3 + 4} = \frac{-1}{1} = -1$$ 5. **Use point-slope form:** The equation of the line is: $$y - y_1 = m(x - x_1)$$ Using point $(-4, -1)$: $$y - (-1) = -1(x - (-4))$$ $$y + 1 = -1(x + 4)$$ 6. **Simplify the equation:** $$y + 1 = -1 \cdot x - 1 \cdot 4$$ $$y + 1 = -x - 4$$ 7. **Isolate $y$:** $$y = -x - 4 - 1$$ $$y = -x - 5$$ **Final answer:** The equation of the line passing through the points $(-4, -1)$ and $(-3, -2)$ is: $$y = -x - 5$$