1. **State the problem:** Find the equation of the line passing through the points $(-2,3)$ and $(-1,1)$ in slope-intercept form $y=mx+b$. 2. **Find the slope $m$:** Use the formula $$m=\frac{y_2-y_1}{x_2-x_1}$$ where $(x_1,y_1)=(-2,3)$ and $(x_2,y_2)=(-1,1)$. 3. Calculate the slope: $$m=\frac{1-3}{-1-(-2)}=\frac{-2}{-1+2}=\frac{-2}{1}=-2$$ 4. **Use point-slope form:** $$y-y_1=m(x-x_1)$$ with $m=-2$ and point $(-2,3)$: $$y-3=-2(x+2)$$ 5. **Simplify:** $$y-3=-2x-4$$ 6. Add 3 to both sides: $$y-\cancel{3}+\cancel{3}=-2x-4+3$$ $$y=-2x-1$$ 7. **Final answer:** The slope-intercept form is $$y=-2x-1$$ which matches the negative slope and descending line described.