1. The problem involves understanding the behavior of two lines: a green solid line passing through points near (-5, 2) and (0, 1), and a red dashed line below it mimicking its shape. 2. To analyze the green line, we first find its equation using the two points given: $(-5, 2)$ and $(0, 1)$. 3. The slope formula is $m = \frac{y_2 - y_1}{x_2 - x_1}$. 4. Substitute the points: $m = \frac{1 - 2}{0 - (-5)} = \frac{-1}{5} = -\frac{1}{5}$. 5. Use point-slope form $y - y_1 = m(x - x_1)$ with point $(0,1)$: $$y - 1 = -\frac{1}{5}(x - 0)$$ 6. Simplify to slope-intercept form: $$y = -\frac{1}{5}x + 1$$ 7. The red dashed line is below the green line and mimics its shape, so it has the same slope but a lower y-intercept. For example: $$y = -\frac{1}{5}x + b$$ with $b < 1$. 8. This explains the relative positions and shapes of the two lines. Final answer: The green line equation is $$y = -\frac{1}{5}x + 1$$ and the red dashed line is parallel with equation $$y = -\frac{1}{5}x + b$$ where $b < 1$.