1. The problem is to graph the line and write the function for $y = 3x + 2$. 2. This is a linear function where the slope is 3 and the y-intercept is 2. 3. To graph, start by plotting the y-intercept at $(0, 2)$. 4. Use the slope 3, which means rise over run is $3/1$, so from $(0, 2)$ move up 3 units and right 1 unit to get the next point $(1, 5)$. 5. Connect these points with a straight line extending in both directions. 6. The function is already given as $y = 3x + 2$. 7. The points you mentioned, $(0, 2)$ and $(2, 8)$ (correcting your calculation: $y = 3(2) + 2 = 6 + 2 = 8$), lie on this line. Final answer: The function is $y = 3x + 2$ and its graph is a straight line passing through $(0, 2)$ and $(2, 8)$ with slope 3.