Subjects algebra

Line Gradient A701C0

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1. **State the problem:** We need to find the gradient (slope) of the line passing through the points approximately (1,1) and (4,6). 2. **Formula for gradient:** The gradient $m$ of a line passing through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Substitute the points:** Using $(x_1,y_1) = (1,1)$ and $(x_2,y_2) = (4,6)$: $$m = \frac{6 - 1}{4 - 1}$$ 4. **Calculate the differences:** $$m = \frac{5}{3}$$ 5. **Interpretation:** The gradient of the line is $\frac{5}{3}$, meaning for every 3 units moved horizontally, the line rises 5 units vertically. **Final answer:** $$\boxed{\frac{5}{3}}$$