1. The problem asks for the gradient of the line given by the equation $y = 11x + 8$. 2. Recall that the equation of a line in slope-intercept form is $y = mx + c$, where $m$ is the gradient (slope) and $c$ is the y-intercept. 3. Comparing $y = 11x + 8$ with $y = mx + c$, we see that $m = 11$. 4. Therefore, the gradient of the line is $11$. The gradient tells us how steep the line is; a gradient of $11$ means the line rises 11 units vertically for every 1 unit it moves horizontally.