1. **State the problem:** Find the gradient and the y-intercept of the line given by the equation $$2y + 7x = 10$$. 2. **Rewrite the equation in slope-intercept form:** Start by isolating $y$: $$2y = -7x + 10$$ Divide both sides by 2: $$y = \frac{-7x + 10}{2}$$ Show cancellation: $$y = \frac{\cancel{2}(-7x + 10)}{\cancel{2} \times 2} = -\frac{7}{2}x + 5$$ 3. **Find the gradient:** The slope-intercept form is $$y = mx + c$$ where $m$ is the gradient. Here, $$m = -\frac{7}{2} = -3.5$$. 4. **Find the y-intercept:** The y-intercept is the value of $y$ when $x=0$. Substitute $x=0$ into the equation: $$y = -3.5(0) + 5 = 5$$ So, the line crosses the y-axis at the point $$(0, 5)$$. **Final answers:** - Gradient of $L$ is $$-3.5$$. - Coordinates of the y-intercept are $$(0, 5)$$.