Subjects algebra

Line Graph 97F59F

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1. **State the problem:** We need to sketch the graph of the equation $$y+2=-3(x+2)$$. 2. **Rewrite the equation in slope-intercept form:** The slope-intercept form is $$y=mx+b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Isolate $y$:** $$y+2=-3(x+2)$$ $$y+2=-3x-6$$ $$y=-3x-6-2$$ $$y=-3x-8$$ 4. **Identify slope and y-intercept:** - Slope $m = -3$ - Y-intercept $b = -8$ 5. **Interpretation:** - The line crosses the y-axis at $(0,-8)$. - The slope $-3$ means for every 1 unit increase in $x$, $y$ decreases by 3 units. 6. **Plot points:** - Start at $(0,-8)$. - From $(0,-8)$, move right 1 unit to $x=1$, then down 3 units to $y=-11$, so point $(1,-11)$. 7. **Draw the line through these points to complete the sketch.**