1. **Problem 24:** Identify the graph of the equation $y=\frac{1}{3}x - 1$. 2. The equation is in slope-intercept form $y=mx+b$ where $m=\frac{1}{3}$ (positive slope) and $b=-1$ (y-intercept below zero). 3. This means the line should slope upward gently (since $\frac{1}{3}$ is positive but less than 1) and cross the y-axis at $-1$. 4. From the descriptions: - Line A slopes downward (negative slope) so it cannot be the answer. - Line B slopes upward from left to right crossing near bottom-left, consistent with positive slope and negative intercept. - Line C slopes upward more steeply, so slope is greater than $\frac{1}{3}$. - Line D slopes downward steeply, so negative slope. - Line E is vertical, so slope undefined. 5. Therefore, **Line B** matches $y=\frac{1}{3}x - 1$. --- 6. **Problem 25:** Identify the graph of an equation $y=mx+b$ where $m>0$ and $b<0$. 7. The line must have a positive slope (upward from left to right) and cross the y-axis below zero. 8. From the descriptions: - Line B slopes upward crossing near bottom-left (positive slope, negative intercept). - Line C slopes upward more steeply crossing near bottom-right (positive slope, but intercept likely positive or near zero). - Line D slopes downward steeply (negative slope). - Line E is vertical (no slope). 9. Only **Line B** fits the criteria $m>0$ and $b<0$. --- **Final answers:** - Problem 24: Line B - Problem 25: Line B