1. The problem asks which graph could represent the line with equation $y = 3x - 4$. 2. The equation is in slope-intercept form $y = mx + b$, where $m = 3$ is the slope and $b = -4$ is the y-intercept. 3. The slope $3$ means the line rises 3 units for every 1 unit it moves to the right, so the line has a positive slope. 4. The y-intercept $-4$ means the line crosses the y-axis at $(0, -4)$, which is below zero. 5. From the descriptions: - Graph A: positive slope, y-intercept below zero (matches $y=3x-4$) - Graph B: negative slope (does not match) - Graph C: positive slope, y-intercept below zero (matches $y=3x-4$) - Graph D: negative slope (does not match) 6. Both Graph A and Graph C have positive slopes and y-intercepts below zero, so either could represent $y=3x-4$. Final answer: Graphs A and C could be the line $y=3x-4$.