1. The problem asks to write the inequality represented by a graph of a downward-sloping solid line passing through points approximately (-3, 0) and (0, -1), with the region shaded above the line. 2. First, find the equation of the line passing through the points (-3, 0) and (0, -1). 3. Calculate the slope $m$ using the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 0}{0 - (-3)} = \frac{-1}{3} = -\frac{1}{3}$$ 4. Use point-slope form with point (0, -1): $$y - (-1) = -\frac{1}{3}(x - 0)$$ $$y + 1 = -\frac{1}{3}x$$ 5. Simplify to slope-intercept form: $$y = -\frac{1}{3}x - 1$$ 6. Since the line is solid, the inequality includes equality ($\leq$ or $\geq$). 7. The region shaded is above the line, so the inequality is: $$y \geq -\frac{1}{3}x - 1$$ 8. Final answer: $$\boxed{y \geq -\frac{1}{3}x - 1}$$