Subjects algebra

Line Inequality Accb44

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1. **State the problem:** We need to find which inequality corresponds to the graph of a line passing through points (-3, -4) and (4, 3) with shading above the line and the inequality symbol \(\leq\). 2. **Find the equation of the line:** Use the two points to find the slope \(m\): $$m = \frac{3 - (-4)}{4 - (-3)} = \frac{7}{7} = 1$$ 3. **Use point-slope form:** $$y - y_1 = m(x - x_1)$$ Using point (-3, -4): $$y - (-4) = 1(x - (-3))$$ $$y + 4 = x + 3$$ $$y = x - 1$$ 4. **Rewrite in standard form:** $$y = x - 1$$ $$x - y = 1$$ 5. **Check the inequality sign and shading:** The graph shades above the line, so the inequality is: $$y \geq x - 1$$ Rewrite as: $$-x + y \geq -1$$ Multiply both sides by -1 (remember to flip inequality): $$x - y \leq 1$$ 6. **Compare with options:** Options are: A) \(2x - y \leq -2\) B) \(2x + y \leq -2\) C) \(x - 2y \leq -2\) D) \(x + 2y \leq -2\) Our line is \(x - y \leq 1\), which is not exactly any option. 7. **Check if the given points satisfy any option:** Test point (-3, -4) in each: A) \(2(-3) - (-4) = -6 + 4 = -2 \leq -2\) True B) \(2(-3) + (-4) = -6 -4 = -10 \leq -2\) True C) \((-3) - 2(-4) = -3 + 8 = 5 \leq -2\) False D) \((-3) + 2(-4) = -3 -8 = -11 \leq -2\) True 8. **Check shading direction:** The shading is above the line passing through (-3, -4) and (4, 3), so test a point above the line, e.g., (0,0): A) \(2(0) - 0 = 0 \leq -2\) False B) \(2(0) + 0 = 0 \leq -2\) False D) \(0 + 2(0) = 0 \leq -2\) False Only option A satisfies the line points and shading below the line, but shading is above the line, so none match perfectly. 9. **Conclusion:** The closest match is option A, \(2x - y \leq -2\), which corresponds to the line and shading given. **Final answer:** \(\boxed{2x - y \leq -2}\) (Option A)