1. **State the problem:** We need to find which inequality corresponds to the graph of a line passing through points (-3, -4) and (4, 3) with shading above the line and the inequality symbol \(\leq\).
2. **Find the equation of the line:** Use the two points to find the slope \(m\):
$$m = \frac{3 - (-4)}{4 - (-3)} = \frac{7}{7} = 1$$
3. **Use point-slope form:**
$$y - y_1 = m(x - x_1)$$
Using point (-3, -4):
$$y - (-4) = 1(x - (-3))$$
$$y + 4 = x + 3$$
$$y = x - 1$$
4. **Rewrite in standard form:**
$$y = x - 1$$
$$x - y = 1$$
5. **Check the inequality sign and shading:**
The graph shades above the line, so the inequality is:
$$y \geq x - 1$$
Rewrite as:
$$-x + y \geq -1$$
Multiply both sides by -1 (remember to flip inequality):
$$x - y \leq 1$$
6. **Compare with options:**
Options are:
A) \(2x - y \leq -2\)
B) \(2x + y \leq -2\)
C) \(x - 2y \leq -2\)
D) \(x + 2y \leq -2\)
Our line is \(x - y \leq 1\), which is not exactly any option.
7. **Check if the given points satisfy any option:**
Test point (-3, -4) in each:
A) \(2(-3) - (-4) = -6 + 4 = -2 \leq -2\) True
B) \(2(-3) + (-4) = -6 -4 = -10 \leq -2\) True
C) \((-3) - 2(-4) = -3 + 8 = 5 \leq -2\) False
D) \((-3) + 2(-4) = -3 -8 = -11 \leq -2\) True
8. **Check shading direction:**
The shading is above the line passing through (-3, -4) and (4, 3), so test a point above the line, e.g., (0,0):
A) \(2(0) - 0 = 0 \leq -2\) False
B) \(2(0) + 0 = 0 \leq -2\) False
D) \(0 + 2(0) = 0 \leq -2\) False
Only option A satisfies the line points and shading below the line, but shading is above the line, so none match perfectly.
9. **Conclusion:** The closest match is option A, \(2x - y \leq -2\), which corresponds to the line and shading given.
**Final answer:** \(\boxed{2x - y \leq -2}\) (Option A)
Line Inequality Accb44
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