1. The problem involves understanding the graph of a line and identifying its equation based on its slope and intercepts. 2. The equation of a line in slope-intercept form is given by $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. The question mentions a line crossing the x-axis at $(0,2)$, which is actually the y-axis intercept, not the x-axis intercept. The x-axis intercept occurs where $y=0$. 4. For the line $y = -2x - 2$, the slope $m = -2$ and the y-intercept $b = -2$. 5. To find the x-intercept, set $y=0$: $$0 = -2x - 2$$ $$2x = -2$$ $$x = \cancel{\frac{2}{2}}1$$ 6. So the x-intercept is at $(1,0)$, not at $(0,2)$. 7. The line with a negative slope crossing the y-axis near 2 is option B, but since the y-intercept here is -2, option D with a slight negative slope crossing below zero is more accurate. 8. The vertical line (option C) cannot be represented by $y = mx + b$ because vertical lines have undefined slope. 9. Therefore, the correct understanding is that the line $y = -2x - 2$ crosses the y-axis at $(0,-2)$ and the x-axis at $(1,0)$. Final answer: The line crosses the y-axis at $(0,-2)$ and the x-axis at $(1,0)$, matching option D more closely than B or C.