1. **Stating the problem:** We are given a line passing through points $(-2,0)$ and $(0,4)$. We need to find: a) The $y$-intercept of the line. b) The gradient (slope) of the line. 2. **Formula for gradient:** The gradient $m$ of a line passing through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Finding the gradient:** Using points $(-2,0)$ and $(0,4)$: $$m = \frac{4 - 0}{0 - (-2)} = \frac{4}{2}$$ 4. **Simplify the fraction:** $$m = \frac{\cancel{4}}{\cancel{2}} = 2$$ So, the gradient of the line is $2$. 5. **Finding the y-intercept:** The $y$-intercept is the point where the line crosses the $y$-axis, i.e., where $x=0$. From the given points, the line passes through $(0,4)$, so the $y$-intercept is $4$. **Final answers:** a) The $y$-intercept is $4$. b) The gradient of the line is $2$.