Subjects algebra

Line Intercepts

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1. The problem is to analyze the line given by the equation $3x - 4y = 12$ and verify its intercepts on the graph. 2. To find the x-intercept, set $y=0$ in the equation: $$3x - 4(0) = 12 \implies 3x = 12 \implies x = 4.$$ So, the x-intercept is at $(4, 0)$. 3. To find the y-intercept, set $x=0$ in the equation: $$3(0) - 4y = 12 \implies -4y = 12 \implies y = -3.$$ So, the y-intercept is at $(0, -3)$. 4. Comparing with the graphs: - Graph 1 shows intercepts at $(0, 3)$ and $(4, 0)$, which matches the x-intercept but the y-intercept is positive 3. - Graph 2 shows intercepts at $(0, 4)$ and $(3, 0)$, which does not match either. 5. Conclusion: The correct intercepts for the line $3x - 4y = 12$ are $(4, 0)$ for the x-axis and $(0, -3)$ for the y-axis, meaning neither graph is an exact match to this equation. Final answer: x-intercept is at $(4, 0)$ and y-intercept is at $(0, -3)$.