1. **State the problem:** We are given the linear equation $2x + y = 6$ and need to find the intercepts where $x=0$ and $y=0$. 2. **Find $y$ when $x=0$ (y-intercept):** Substitute $x=0$ into the equation: $$2(0) + y = 6$$ $$y = 6$$ So, the y-intercept is at $(0,6)$. 3. **Find $x$ when $y=0$ (x-intercept):** Substitute $y=0$ into the equation: $$2x + 0 = 6$$ $$2x = 6$$ Divide both sides by 2: $$\cancel{2}x = \cancel{2}3$$ $$x = 3$$ So, the x-intercept is at $(3,0)$. 4. **Summary:** - The y-intercept is $(0,6)$. - The x-intercept is $(3,0)$. These points can be used to graph the line $2x + y = 6$ easily.