1. **State the problem:** Find the x-intercept and y-intercept of the line given by the equation $8x + 10y = 20$. 2. **Recall the intercept rules:** - The x-intercept occurs where $y=0$. - The y-intercept occurs where $x=0$. 3. **Find the x-intercept:** Set $y=0$ in the equation: $$8x + 10(0) = 20$$ $$8x = 20$$ Divide both sides by 8: $$\cancel{8}x = \frac{20}{\cancel{8}}$$ $$x = \frac{20}{8} = \frac{5}{2} = 2.5$$ So, the x-intercept is at $(2.5, 0)$. 4. **Find the y-intercept:** Set $x=0$ in the equation: $$8(0) + 10y = 20$$ $$10y = 20$$ Divide both sides by 10: $$\cancel{10}y = \frac{20}{\cancel{10}}$$ $$y = 2$$ So, the y-intercept is at $(0, 2)$. **Final answer:** - x-intercept: $(2.5, 0)$ - y-intercept: $(0, 2)$