1. **State the problem:** Graph the line given by the equation $$9x + 63y = 630$$ using intercepts. 2. **Formula and rules:** To graph a line using intercepts, find where the line crosses the x-axis and y-axis. - The x-intercept is found by setting $$y=0$$ and solving for $$x$$. - The y-intercept is found by setting $$x=0$$ and solving for $$y$$. 3. **Find the x-intercept:** Set $$y=0$$ in the equation: $$9x + 63(0) = 630$$ $$9x = 630$$ Divide both sides by 9: $$\cancel{9}x = \frac{630}{\cancel{9}}$$ $$x = 70$$ So, the x-intercept is at $$(70, 0)$$. 4. **Find the y-intercept:** Set $$x=0$$ in the equation: $$9(0) + 63y = 630$$ $$63y = 630$$ Divide both sides by 63: $$\cancel{63}y = \frac{630}{\cancel{63}}$$ $$y = 10$$ So, the y-intercept is at $$(0, 10)$$. 5. **Plot the points:** Plot the points $$(70, 0)$$ and $$(0, 10)$$ on the graph. 6. **Draw the line:** Draw a straight line through these two points. This line represents the equation $$9x + 63y = 630$$. **Final answer:** The line crosses the x-axis at $$(70, 0)$$ and the y-axis at $$(0, 10)$$.