Subjects algebra

Line Intercepts Bb5B81

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1. **Problem Statement:** Find the x-intercept and y-intercept of the line passing through points (-3,0) and (0,3). 2. **Formula and Rules:** - The x-intercept is the point where the line crosses the x-axis, so $y=0$. - The y-intercept is the point where the line crosses the y-axis, so $x=0$. - The equation of a line can be found using the slope-intercept form: $$y=mx+b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Find the slope $m$:** $$m=\frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 0}{0 - (-3)} = \frac{3}{3} = 1$$ 4. **Find the y-intercept $b$:** Since the line passes through $(0,3)$, the y-intercept is $b=3$. 5. **Write the equation of the line:** $$y = 1 \cdot x + 3 = x + 3$$ 6. **Find the x-intercept:** Set $y=0$ and solve for $x$: $$0 = x + 3$$ $$x = -3$$ 7. **Summary:** - x-intercept is at $(-3,0)$ - y-intercept is at $(0,3)$