1. Let's analyze the given linear equations and find the intercepts. 2. The equation given is $y = \frac{8}{3}x - 4$. 3. The y-intercept occurs when $x=0$. Substitute $x=0$ into the equation: $$y = \frac{8}{3} \times 0 - 4 = -4$$ So, the y-intercept is indeed $-4$. 4. The x-intercept occurs when $y=0$. Set $y=0$ and solve for $x$: $$0 = \frac{8}{3}x - 4$$ Add 4 to both sides: $$4 = \frac{8}{3}x$$ Divide both sides by $\frac{8}{3}$: $$x = \frac{4}{\frac{8}{3}} = 4 \times \frac{3}{8} = \frac{12}{8}$$ Simplify the fraction: $$x = \frac{\cancel{12}^{3}}{\cancel{8}^{2}} = \frac{3}{2}$$ 5. Therefore, the x-intercept is $\frac{3}{2}$, not $\frac{2}{3}$. 6. Summary: - Y-intercept: $-4$ (correct) - X-intercept: $\frac{3}{2}$ (not $\frac{2}{3}$)