1. **Stating the problem:** We have the line equation $$3x - 2y = a$$ and it cuts the y-axis at point $$P(0,4)$$. We need to find the constant $$a$$ and then find the x-intercept point $$Q$$ where the line cuts the x-axis. 2. **Finding the value of $$a$$:** The y-axis is where $$x=0$$. Substitute $$x=0$$ and $$y=4$$ into the equation: $$3(0) - 2(4) = a$$ $$0 - 8 = a$$ $$a = -8$$ 3. **Finding the x-intercept $$Q$$:** The x-intercept occurs where $$y=0$$. Substitute $$y=0$$ and $$a=-8$$ into the equation: $$3x - 2(0) = -8$$ $$3x = -8$$ $$x = \frac{-8}{3}$$ So, the coordinates of $$Q$$ are $$\left( -\frac{8}{3}, 0 \right)$$. **Final answers:** - $$a = -8$$ - $$Q = \left( -\frac{8}{3}, 0 \right)$$