1. **State the problem:** Find the point of intersection of the two lines given by the equations: $$y = -3x + 20$$ $$y = -2x + 12$$ 2. **Formula and approach:** To find the intersection, set the two expressions for $y$ equal to each other because at the intersection point, both $y$ values are the same. $$-3x + 20 = -2x + 12$$ 3. **Solve for $x$:** $$-3x + 20 = -2x + 12$$ $$-3x + 20 + 3x = -2x + 12 + 3x$$ $$20 = x + 12$$ $$20 - 12 = x$$ $$x = 8$$ 4. **Find $y$ by substituting $x=8$ into one of the original equations:** Using $y = -3x + 20$: $$y = -3(8) + 20$$ $$y = -24 + 20$$ $$y = -4$$ 5. **Conclusion:** The two lines intersect at the point $$(8, -4)$$ This means when $x=8$, both lines have the same $y$ value of $-4$.