1. **State the problem:** Find the intersection point of the two lines given by the equations:
$$2x = y + 5$$
and
$$6x + 2y = -5$$
2. **Rewrite the first equation to express $y$ in terms of $x$: **
$$2x = y + 5 \implies y = 2x - 5$$
3. **Substitute $y = 2x - 5$ into the second equation:**
$$6x + 2(2x - 5) = -5$$
4. **Simplify the equation:**
$$6x + 4x - 10 = -5$$
$$10x - 10 = -5$$
5. **Add 10 to both sides:**
$$10x - 10 + 10 = -5 + 10$$
$$10x = 5$$
6. **Divide both sides by 10:**
$$\cancel{10}x = \frac{5}{\cancel{10}}$$
$$x = \frac{1}{2}$$
7. **Substitute $x = \frac{1}{2}$ back into $y = 2x - 5$ to find $y$: **
$$y = 2 \times \frac{1}{2} - 5 = 1 - 5 = -4$$
8. **Conclusion:** The lines intersect at the point $$\left(\frac{1}{2}, -4\right)$$.
**Answer:** $\boxed{\left(\frac{1}{2}, -4\right)}$
Line Intersection 3E6A3B
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