1. The problem asks to find the ordered pair that is a solution to both equations represented by the two lines on the graph. 2. The first line passes through points (-6, -6) and (6, 6), so its slope is calculated as $$m=\frac{6-(-6)}{6-(-6)}=\frac{12}{12}=1$$ and the equation is $$y=x$$. 3. The second line passes through points (-2, 6) and (2, -6), so its slope is $$m=\frac{-6-6}{2-(-2)}=\frac{-12}{4}=-3$$. 4. Using point-slope form for the second line with point (-2, 6): $$y-6=-3(x+2)$$ which simplifies to $$y-6=-3x-6$$ and then $$y=-3x$$. 5. To find the solution to both equations, solve the system: $$\begin{cases} y=x \\ y=-3x \end{cases}$$ 6. Substitute $y=x$ into $y=-3x$: $$x=-3x$$ 7. Add $3x$ to both sides: $$x+3x=0$$ $$4x=0$$ 8. Divide both sides by 4: $$\cancel{4}x=\cancel{4}0$$ $$x=0$$ 9. Substitute $x=0$ back into $y=x$: $$y=0$$ 10. The solution to the system is the ordered pair $(0,0)$. 11. Checking the given options, none is $(0,0)$, but the graph shows the intersection near $(-1,-1)$, so let's verify if $(-1,-1)$ satisfies both equations. 12. For $y=x$, at $x=-1$, $y=-1$ which matches. 13. For $y=-3x$, at $x=-1$, $y=-3(-1)=3$, which does not match $-1$. 14. So $(-1,-1)$ is not a solution to both equations. 15. Check $(-3,-1)$: For $y=x$, $y=-3$ but given $y=-1$, no match. For $y=-3x$, $y=-3(-3)=9$, no match. 16. Check $(-3,-2)$: For $y=x$, $y=-3$ but given $y=-2$, no match. For $y=-3x$, $y=-3(-3)=9$, no match. 17. Check $(-2,-2)$: For $y=x$, $y=-2$ matches. For $y=-3x$, $y=-3(-2)=6$, no match. 18. None of the given points satisfy both equations exactly, but the graph shows the lines intersect near $(-1,-1)$. 19. The first line is $y=x$. 20. The second line passes through (-2,6) and (2,-6), slope $-3$, equation $y=-3x$. 21. The only solution to both equations is $(0,0)$, which is not listed. 22. Since the problem asks which ordered pair represents a solution to both equations, and none of the options satisfy both equations exactly, the closest intersection point is $(-1,-1)$, which satisfies the first equation but not the second. Final answer: None of the given ordered pairs is the exact solution to both equations, but $(-1,-1)$ is the closest to the intersection point shown on the graph.