Subjects algebra

Line Intersection 4E1296

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1. **State the problem:** We are given two equations: $$y = -\frac{5}{4}x + 3$$ and $$y = 8$$ We need to find the point of intersection of these two lines. 2. **Set the equations equal to find the intersection:** Since both expressions equal $y$, set them equal: $$-\frac{5}{4}x + 3 = 8$$ 3. **Solve for $x$:** Subtract 3 from both sides: $$-\frac{5}{4}x + 3 - 3 = 8 - 3$$ $$-\frac{5}{4}x = 5$$ 4. **Isolate $x$ by dividing both sides by $-\frac{5}{4}$:** $$x = \frac{5}{-\frac{5}{4}}$$ Write division as multiplication by reciprocal: $$x = 5 \times -\frac{4}{5}$$ 5. **Simplify:** $$x = \cancel{5} \times -\frac{4}{\cancel{5}} = -4$$ 6. **Find $y$ by substituting $x = -4$ into $y = 8$:** $$y = 8$$ 7. **Final answer:** The lines intersect at the point $$\boxed{(-4, 8)}$$.