1. **State the problem:** Find the point of intersection of the two lines given by the equations: $$2x + 3y = 11$$ $$2x + y = 5$$ 2. **Formula and method:** To find the intersection point, solve the system of linear equations simultaneously. We can use substitution or elimination. Here, we use elimination. 3. **Eliminate $x$:** Subtract the second equation from the first: $$ (2x + 3y) - (2x + y) = 11 - 5 $$ $$ 2x + 3y - 2x - y = 6 $$ $$ 2y = 6 $$ 4. **Solve for $y$:** $$ y = \frac{6}{2} $$ $$ y = 3 $$ 5. **Substitute $y=3$ into one of the original equations:** Using the second equation: $$ 2x + y = 5 $$ $$ 2x + 3 = 5 $$ $$ 2x = 5 - 3 $$ $$ 2x = 2 $$ 6. **Solve for $x$:** $$ x = \frac{2}{2} $$ $$ x = 1 $$ 7. **Conclusion:** The point of intersection is at $$ (x, y) = (1, 3) $$ This means the two lines cross at the point with coordinates $1$ on the x-axis and $3$ on the y-axis.