1. **State the problem:** We need to find the slope $m$ and the y-intercept $c$ of the line $Q$ given two points on the line: $(0, -2)$ and $(1, 2)$. 2. **Formula for slope:** The slope $m$ of a line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Calculate the slope:** Using the points $(0, -2)$ and $(1, 2)$: $$m = \frac{2 - (-2)}{1 - 0} = \frac{2 + 2}{1} = \frac{4}{1} = 4$$ 4. **Find the y-intercept $c$:** The y-intercept is the value of $y$ when $x=0$. From the point $(0, -2)$, we see directly that: $$c = -2$$ 5. **Write the equation of the line:** Substitute $m=4$ and $c=-2$ into the slope-intercept form $y = mx + c$: $$y = 4x - 2$$ **Final answer:** The slope $m$ is 4 and the y-intercept $c$ is -2.