1. **State the problem:** We need to find the slope $m$ and the y-intercept $c$ of the line $Q$ given by the equation $y = mx + c$. 2. **Identify points on the line:** From the description, the line passes through points $(0,1)$ and $(1,4)$. 3. **Calculate the slope $m$:** The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ Using points $(0,1)$ and $(1,4)$: $$m = \frac{4 - 1}{1 - 0} = \frac{3}{1} = 3$$ 4. **Find the y-intercept $c$:** The y-intercept is the value of $y$ when $x=0$. From the point $(0,1)$, we see directly that: $$c = 1$$ 5. **Write the equation of the line:** Substituting $m=3$ and $c=1$ into $y = mx + c$ gives: $$y = 3x + 1$$ **Final answer:** $m = 3$, $c = 1$