1. **State the problem:** We need to find the values of $m$ (slope) and $c$ (y-intercept) for the line $Q$ given its equation in the form $y = mx + c$. 2. **Identify points on the line:** From the graph description, the line passes through points $(0, -3)$ and $(1, 2)$. 3. **Formula for slope:** The slope $m$ is calculated by the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ where $(x_1, y_1) = (0, -3)$ and $(x_2, y_2) = (1, 2)$. 4. **Calculate slope:** $$m = \frac{2 - (-3)}{1 - 0} = \frac{2 + 3}{1} = \frac{5}{1} = 5$$ 5. **Identify y-intercept:** The y-intercept $c$ is the value of $y$ when $x=0$, which is given as $-3$. 6. **Write the equation:** Substituting $m=5$ and $c=-3$ into the equation $y = mx + c$ gives: $$y = 5x - 3$$ **Final answer:** $m = 5$, $c = -3$