1. The problem is to find 4 points to plot on the graph for the two lines given by the equations $y = x + 1$ and $y = 2x - 3$. 2. For each line, we can find points by choosing values for $x$ and calculating the corresponding $y$ using the equation. 3. For the first line $y = x + 1$: - If $x = 0$, then $y = 0 + 1 = 1$, so point $(0,1)$. - If $x = 1$, then $y = 1 + 1 = 2$, so point $(1,2)$. 4. For the second line $y = 2x - 3$: - If $x = 0$, then $y = 2(0) - 3 = -3$, so point $(0,-3)$. - If $x = 1$, then $y = 2(1) - 3 = 2 - 3 = -1$, so point $(1,-1)$. 5. These points are easy to calculate and plot, and they clearly show the slope and intercept of each line. Final points to plot: - Line 1: $(0,1)$ and $(1,2)$ - Line 2: $(0,-3)$ and $(1,-1)$