1. **State the problem:** We need to determine which ordered pairs lie on the graph of the equation $$y = -\frac{2}{3}x + \frac{2}{3}$$. 2. **Recall the formula:** For each point $(x,y)$, substitute $x$ into the equation and check if the resulting $y$ matches the given $y$. 3. **Check each point:** - For $(3,4)$: $$y = -\frac{2}{3} \times 3 + \frac{2}{3} = -2 + \frac{2}{3} = -\frac{6}{3} + \frac{2}{3} = -\frac{4}{3} \neq 4$$ Not on the line. - For $(-2,2)$: $$y = -\frac{2}{3} \times (-2) + \frac{2}{3} = \frac{4}{3} + \frac{2}{3} = 2$$ Matches $y=2$, so on the line. - For $(1,0)$: $$y = -\frac{2}{3} \times 1 + \frac{2}{3} = -\frac{2}{3} + \frac{2}{3} = 0$$ Matches $y=0$, so on the line. - For $(-5,4)$: $$y = -\frac{2}{3} \times (-5) + \frac{2}{3} = \frac{10}{3} + \frac{2}{3} = 4$$ Matches $y=4$, so on the line. - For $(7,-4)$: $$y = -\frac{2}{3} \times 7 + \frac{2}{3} = -\frac{14}{3} + \frac{2}{3} = -4$$ Matches $y=-4$, so on the line. - For $(4,-2)$: $$y = -\frac{2}{3} \times 4 + \frac{2}{3} = -\frac{8}{3} + \frac{2}{3} = -2$$ Matches $y=-2$, so on the line. 4. **Conclusion:** The points $(-2,2)$, $(1,0)$, $(-5,4)$, $(7,-4)$, and $(4,-2)$ lie on the graph, but $(3,4)$ does not.