Subjects algebra

Line Points Journey

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1. The problem involves verifying points on the line given by the equation $x - y = 2$ and understanding the journey distance graph. 2. The equation of the line is $x - y = 2$. This means for any point $(x,y)$ on the line, substituting $x$ and $y$ into the equation should satisfy it. 3. Check point A(-2, 0): Substitute $x = -2$, $y = 0$ into $x - y$: $$-2 - 0 = -2$$ Since $-2 \neq 2$, point A is not on the line $x - y = 2$. 4. Check point C(0, -2): Substitute $x = 0$, $y = -2$: $$0 - (-2) = 0 + 2 = 2$$ This equals 2, so point C lies on the line. 5. Check point D(2, 0): Substitute $x = 2$, $y = 0$: $$2 - 0 = 2$$ This equals 2, so point D lies on the line. 6. The line passing through points A and D is $x - y = 2$; however, point A does not satisfy the equation, so the correct line through D and C is $x - y = 2$. 7. For the journey graph, when Emma and Julianna have traveled 100 km, the graph shows they still have about 50 km to go. Final answers: - Points on the line $x - y = 2$ are C(0, -2) and D(2, 0). - Emma and Julianna have about 50 km left after traveling 100 km.