1. **State the problem:** We need to draw and understand the graph of the line given by the equation $y = 4x - 4$. 2. **Recall the formula:** The equation of a straight line in slope-intercept form is $y = mx + c$, where $m$ is the gradient (slope) and $c$ is the y-intercept. 3. **Identify the gradient and intercept:** Here, $m = 4$ (positive gradient) and $c = -4$ (y-intercept). 4. **Plot key points:** - When $x=0$, $y = 4(0) - 4 = -4$ (point $(0, -4)$). - When $x=1$, $y = 4(1) - 4 = 0$ (point $(1, 0)$). - When $x=-1$, $y = 4(-1) - 4 = -8$ (point $(-1, -8)$). 5. **Draw the line:** Connect these points to form a straight line with positive slope crossing the y-axis at $-4$. 6. **Note on the user’s points:** The user mentioned points $(0, -6)$ and $(2, 0)$ which do not satisfy $y=4x-4$. The correct points for this equation are as above. **Final answer:** The line $y=4x-4$ has a positive gradient of 4 and crosses the y-axis at $-4$. It passes through points $(0,-4)$, $(1,0)$, and $(-1,-8)$.