Subjects algebra

Line Properties 825126

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1. **State the problem:** Find the slope $m$, y-intercept $b$, y-intercept coordinate $yint$, x-intercept coordinate $xint$, and the equation in point-slope form $pref$ for the line given by the formula $y = \frac{3}{7}x - 2$. 2. **Identify slope and y-intercept:** The formula is in slope-intercept form $y = mx + b$, so $m = \frac{3}{7}$ and $b = -2$. 3. **Find y-intercept coordinate ($yint$):** The y-intercept occurs when $x=0$, so $yint = (0, b) = (0, -2)$. 4. **Find x-intercept coordinate ($xint$):** The x-intercept occurs when $y=0$, solve $0 = \frac{3}{7}x - 2$. $$ \frac{3}{7}x - 2 = 0 $$ $$ \frac{3}{7}x = 2 $$ $$ x = 2 \times \frac{7}{3} = \frac{14}{3} $$ So, $xint = \left(\frac{14}{3}, 0\right)$. 5. **Write point-slope form ($pref$):** Using point-slope form $y - y_1 = m(x - x_1)$ and the y-intercept point $(0, -2)$, $$ y - (-2) = \frac{3}{7}(x - 0) $$ $$ y + 2 = \frac{3}{7}x $$ So, $pref = y + 2 = \frac{3}{7}x$.