1. The problem asks for the equation of the image of the line $y = \frac{1}{2}x + 3$ after reflection over the mirror line $y = 0$. 2. Reflection over the line $y=0$ (the x-axis) changes the sign of the $y$-coordinate of every point on the line. This means the new line's equation will have the $y$ values negated. 3. The original line is $y = \frac{1}{2}x + 3$. 4. Reflecting over $y=0$ means replacing $y$ by $-y$ or equivalently, the new line is $y' = -y$. 5. Substitute $y$ from the original equation: $$y' = -\left(\frac{1}{2}x + 3\right) = -\frac{1}{2}x - 3$$ 6. So the equation of the reflected line is: $$y = -\frac{1}{2}x - 3$$ 7. This matches the option $y = -(1/2)x - 3$. Final answer: $y = -\frac{1}{2}x - 3$