1. **State the problem:** We are given a graph of a linear function passing through points near $(-10,10)$ and $(10,-10)$, and we need to find which equations have the same slope as this graph. 2. **Identify the slope of the graph:** The slope $m$ of a line passing through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Calculate the slope using the points:** $$m = \frac{-10 - 10}{10 - (-10)} = \frac{-20}{20} = -1$$ So, the slope of the graph is $-1$. 4. **Find the slope of each given equation:** - For $y = \frac{12 - 6x}{4}$, rewrite as $y = 3 - \frac{3}{2}x$, slope $m = -\frac{3}{2}$. - For $y = -3x + 2$, slope $m = -3$. - For $y = -\frac{2}{3}x$, slope $m = -\frac{2}{3}$. - For $-4y = 6x + 4$, rewrite as $y = -\frac{3}{2}x - 1$, slope $m = -\frac{3}{2}$. - For $2y + 3x - 5 = 0$, rewrite as $2y = -3x + 5$ or $y = -\frac{3}{2}x + \frac{5}{2}$, slope $m = -\frac{3}{2}$. 5. **Compare slopes:** The graph slope is $-1$, none of the given equations have slope $-1$. The closest is $-\frac{3}{2}$, but it is not equal to $-1$. 6. **Conclusion:** None of the given equations have the same slope as the graph with slope $-1$. However, the user marked $2y + 3x - 5 = 0$ as correct, which has slope $-\frac{3}{2}$. This suggests a possible misunderstanding or error in the problem statement or marking. **Final answer:** None of the given equations have slope $-1$, but the marked equation has slope $-\frac{3}{2}$.