1. **Stating the problem:** We are given a line on a coordinate plane with points approximately at (-9,5) and (6,-4), and we want to find the slope of this line. 2. **Formula for slope:** The slope $m$ of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Identify points:** From the graph description, take the points: $$ (x_1,y_1) = (-9,5), \quad (x_2,y_2) = (6,-4) $$ 4. **Calculate the differences:** $$ y_2 - y_1 = -4 - 5 = -9 $$ $$ x_2 - x_1 = 6 - (-9) = 6 + 9 = 15 $$ 5. **Calculate the slope:** $$ m = \frac{-9}{15} $$ 6. **Simplify the fraction:** $$ m = \frac{\cancel{-9}}{\cancel{15}} = \frac{-3}{5} $$ 7. **Interpretation:** The slope is $-\frac{3}{5}$, which means the line goes down 3 units vertically for every 5 units it moves horizontally to the right. **Final answer:** $$ m = -\frac{3}{5} $$