1. The problem asks for the slope of the line passing through the points $(-3,-8)$ and $(3,8)$. 2. The formula for the slope $m$ of a line through two points $(x_1,y_1)$ and $(x_2,y_2)$ is: $$m=\frac{y_2-y_1}{x_2-x_1}$$ 3. Substitute the given points into the formula: $$m=\frac{8-(-8)}{3-(-3)}$$ 4. Simplify the numerator and denominator: $$m=\frac{8+8}{3+3}$$ 5. This becomes: $$m=\frac{16}{6}$$ 6. Simplify the fraction by dividing numerator and denominator by their greatest common divisor 2: $$m=\frac{\cancel{16}^8}{\cancel{6}^3}$$ 7. The slope of the line is: $$m=\frac{8}{3}$$ This means the line rises 8 units vertically for every 3 units it moves horizontally to the right.