1. **State the problem:** Find the slope of the line passing through the points $(-3, 12)$ and $(-11, 2)$.
2. **Formula for slope:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
This formula calculates the "rise" over the "run" or the change in $y$ divided by the change in $x$.
3. **Substitute the given points:**
$$m = \frac{2 - 12}{-11 - (-3)}$$
4. **Simplify numerator and denominator:**
$$m = \frac{-10}{-11 + 3}$$
5. **Simplify the denominator:**
$$m = \frac{-10}{-8}$$
6. **Cancel common negative signs:**
$$m = \frac{\cancel{-}10}{\cancel{-}8} = \frac{10}{8}$$
7. **Simplify the fraction:**
$$m = \frac{10 \div 2}{8 \div 2} = \frac{5}{4}$$
**Final answer:** The slope of the line passing through $(-3, 12)$ and $(-11, 2)$ is $\boxed{\frac{5}{4}}$.
Line Slope 8F2F91
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