Subjects algebra

Line Slope Bad38D

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1. **State the problem:** We need to find the slope of the line passing through points approximately (-7, -9) and (6, 10) on the Cartesian plane. 2. **Formula for slope:** The slope $m$ of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ This formula represents the "rise" (change in $y$) over the "run" (change in $x$). 3. **Identify points:** From the graph, the two points are: $$ (x_1, y_1) = (-7, -9) \quad \text{and} \quad (x_2, y_2) = (6, 10) $$ 4. **Calculate rise and run:** $$ \text{rise} = y_2 - y_1 = 10 - (-9) = 10 + 9 = 19 $$ $$ \text{run} = x_2 - x_1 = 6 - (-7) = 6 + 7 = 13 $$ 5. **Calculate slope:** $$ m = \frac{19}{13} $$ This fraction is already in simplest form since 19 and 13 have no common factors other than 1. 6. **Interpretation:** The slope $\frac{19}{13}$ means for every 13 units moved horizontally (run), the line rises 19 units vertically (rise). **Final answer:** The slope of the line is $$ m = \frac{19}{13} $$