1. **State the problem:** Put the equation $3x - y = -6$ into slope-intercept form. 2. **Recall the slope-intercept form:** The slope-intercept form of a line is given by $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Isolate $y$ on one side:** Starting with the equation $$3x - y = -6$$ subtract $3x$ from both sides: $$3x - y - 3x = -6 - 3x$$ which simplifies to $$-y = -6 - 3x$$ 4. **Multiply both sides by $-1$ to solve for $y$:** $$\cancel{-1} \times (-y) = \cancel{-1} \times (-6 - 3x)$$ which gives $$y = 6 + 3x$$ 5. **Rewrite in slope-intercept form:** $$y = 3x + 6$$ **Final answer:** The slope-intercept form is $$y = 3x + 6$$.