1. **State the problem:** We are given a line with equation $y = ax + b$. We need to find the values of $a$ (slope) and $b$ (y-intercept). 2. **Identify given information:** - The line crosses the y-axis at 3, so $b = 3$. - The line crosses the x-axis at 5, so when $y=0$, $x=5$. 3. **Use the x-intercept to find $a$:** At the x-intercept, $y=0$, so: $$0 = a \times 5 + b$$ Substitute $b=3$: $$0 = 5a + 3$$ 4. **Solve for $a$:** $$5a = -3$$ $$a = \frac{-3}{5}$$ 5. **Final answer:** $$a = -\frac{3}{5}, \quad b = 3$$ This means the line equation is: $$y = -\frac{3}{5}x + 3$$