1. **State the problem:** Find the equation of the line with slope 2 passing through the point $(-1,6)$. 2. **Formula used:** The point-slope form of a line is given by $$y - y_1 = m(x - x_1)$$ where $m$ is the slope and $(x_1,y_1)$ is a point on the line. 3. **Substitute the known values:** Here, $m=2$, $x_1=-1$, and $y_1=6$. $$y - 6 = 2(x - (-1))$$ $$y - 6 = 2(x + 1)$$ 4. **Simplify the right side:** $$y - 6 = 2x + 2$$ 5. **Isolate $y$ to get slope-intercept form:** $$y = 2x + 2 + 6$$ $$y = 2x + 8$$ 6. **Final answer:** The equation of the line is $$y = 2x + 8$$