1. **Problem statement:** Calculate the slope (malda) of the lines p and q given their points. 2. **Formula for slope:** The slope $m$ of a line passing through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m=\frac{y_2 - y_1}{x_2 - x_1}$$ This formula calculates the rate of change of $y$ with respect to $x$. 3. **Calculate slope of line p:** Points are $(-6,-6)$ and $(4,2)$. $$m_p=\frac{2 - (-6)}{4 - (-6)}=\frac{2 + 6}{4 + 6}=\frac{8}{10}$$ Simplify the fraction: $$m_p=\frac{\cancel{8}}{\cancel{10}}=\frac{4}{5}$$ So, the slope of line p is $\frac{4}{5}$. 4. **Calculate slope of line q:** Points are $(-4,4)$ and $(6,-6)$. $$m_q=\frac{-6 - 4}{6 - (-4)}=\frac{-10}{10}$$ Simplify the fraction: $$m_q=\frac{\cancel{-10}}{\cancel{10}}=-1$$ So, the slope of line q is $-1$. **Final answers:** - Slope of line p: $\frac{4}{5}$ - Slope of line q: $-1$