1. **State the problem:** We need to determine which ordered pairs satisfy the equation $$y = -\frac{2}{3}x + \frac{2}{3}$$. 2. **Recall the formula:** For each ordered pair $(x,y)$, substitute $x$ into the right side of the equation and check if the result equals $y$. 3. **Check each ordered pair:** - For $(4, -2)$: $$y = -\frac{2}{3} \times 4 + \frac{2}{3} = -\frac{8}{3} + \frac{2}{3} = -\frac{6}{3} = -2$$ Matches $y = -2$, so $(4, -2)$ is a solution. - For $(7, -4)$: $$y = -\frac{2}{3} \times 7 + \frac{2}{3} = -\frac{14}{3} + \frac{2}{3} = -\frac{12}{3} = -4$$ Matches $y = -4$, so $(7, -4)$ is a solution. - For $(3, 4)$: $$y = -\frac{2}{3} \times 3 + \frac{2}{3} = -2 + \frac{2}{3} = -\frac{6}{3} + \frac{2}{3} = -\frac{4}{3} \neq 4$$ Does not match, so $(3, 4)$ is not a solution. - For $(1, 0)$: $$y = -\frac{2}{3} \times 1 + \frac{2}{3} = -\frac{2}{3} + \frac{2}{3} = 0$$ Matches $y = 0$, so $(1, 0)$ is a solution. - For $(-2, 2)$: $$y = -\frac{2}{3} \times (-2) + \frac{2}{3} = \frac{4}{3} + \frac{2}{3} = 2$$ Matches $y = 2$, so $(-2, 2)$ is a solution. - For $(-5, 4)$: $$y = -\frac{2}{3} \times (-5) + \frac{2}{3} = \frac{10}{3} + \frac{2}{3} = 4$$ Matches $y = 4$, so $(-5, 4)$ is a solution. 4. **Final answer:** The ordered pairs that are solutions are $(4, -2)$, $(7, -4)$, $(1, 0)$, $(-2, 2)$, and $(-5, 4)$.